How do I list all files of a directory?

os.listdir() will get you everything that's in a directory - files and directories.

If you want just files, you could either filter this down using os.path:

from os import listdir
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]

or you could use os.walk() which will yield two lists for each directory it visits - splitting into files and dirs for you. If you only want the top directory you can just break the first time it yields

from os import walk

f = []
for (dirpath, dirnames, filenames) in walk(mypath):

I prefer using the glob module, as it does pattern matching and expansion.

import glob

It will return a list with the queried files:

['/home/adam/file1.txt', '/home/adam/file2.txt', .... ]
import os

will return a list of all files and directories in "somedirectory".